Why a network is not one long pipe
A single-pipe calculation assumes the same flow from the compressor room to the last user. Real distribution systems do not work that way. Trunk flow falls after every take-off, parallel paths share flow according to their resistance, and the pressure at a remote machine depends on every segment upstream of it. One undersized drop or a long, narrow branch can dominate a pressure complaint even when the main header is generously sized.
That is why the calculator treats the system as a network. It is meant for engineering screening, troubleshooting and comparing options before money is spent on pipework or on raising compressor pressure. Raising discharge pressure to overcome a distribution problem is the expensive answer: each extra bar typically costs about 7% more compressor power, and every leak in the plant then flows faster.
For single runs or new header sizing, the simpler compressed air pipe sizing calculator is often enough. The network tool is for existing plants with several branches, loops or more than one source.
What the calculator works out
| Network type | Calculation approach | Main output |
|---|---|---|
| Branched (tree) layout | Live tool: a single-source tree (one trunk, one junction, up to three branches); Live tool: a single-source tree (one trunk, one junction, up to three branches); adds up downstream demand into each upstream segment | Pressure drop in every segment and pressure at every node |
| Ring main or loop | Assessed in a pressure-drop audit, not by the live tool: flow is split iteratively until it balances at every node and pressure drops around each loop cancel; multi-source networks are assessed the same way | Balanced flows in each path and node pressures |
| Scenario comparison | Run the live tool again for the same tree layout with changed demand or pipe size | Before and after pressure profile |
| Field calibration | Done in a pressure-drop audit: Done in a pressure-drop audit: compares calculated node pressures with measured pressures | Gaps that point to hidden restrictions, blocked filters or wrong drawings |
How the network is described
The network is entered as a set of nodes and segments.
- Source nodes: compressor room outlets or dryer outlets, with their supply pressure in bar g and air temperature.
- Junction nodes: tees and headers where flow divides.
- Demand nodes: machines or areas, with their flow (normally as FAD in m³/min or cfm) and the minimum pressure each needs to work properly.
- Segments: each physical pipe run between two nodes, with its actual internal diameter, length, material and roughness, plus an allowance for fittings and valves.
Use the real internal diameter, not the nominal size. A nominal 25 mm medium-grade steel pipe has an internal diameter of about 27 mm, while some plastic and aluminium systems differ noticeably for the same nominal size. Corroded old steel pipe can also have a much rougher bore than new pipe, which raises friction.
Method: the engineering behind the numbers
- Convert flow. Demand is entered as free air but friction depends on the actual volume flowing at line pressure. The calculator converts FAD to actual flow using the absolute line pressure and temperature, via the FAD and reference condition conversion tool method.
- Calculate velocity and Reynolds number. Velocity v = actual volume flow ÷ pipe area. The Reynolds number shows that compressed-air flow in plant pipework is almost always turbulent.
- Find the friction factor. The Colebrook equation, or an explicit approximation such as Swamee–Jain, gives the Darcy friction factor f from roughness and Reynolds number.
- Calculate segment pressure drop. Darcy–Weisbach: Δp = f × (L ÷ D) × (ρ × v² ÷ 2), where L includes the equivalent length of bends, tees and valves, and ρ is the air density at line pressure.
- Solve the network. For a tree, add flows from the far end back to the source and subtract drops from the source outward. For loops, which are assessed in a pressure-drop audit rather than by the live tool, a Hardy Cross style iteration adjusts the flow split until each loop’s pressure drops sum to zero.
- Identify the critical path. The node with the smallest margin between calculated pressure and its required minimum is the critical node. The segments on the way to it are the ones worth improving.
Because air density changes with pressure, segments far from the source, where pressure is lower, give slightly higher drops at the same free-air flow. For long lines or large drops, the calculator updates density segment by segment instead of using one value for the whole system.
Worked example: finding the critical branch
The figures below are illustrative, using steel pipe and an air temperature of about 30 °C. Lengths include an allowance for fittings.
- Trunk: 60 m of nominal 50 mm pipe (internal diameter about 52.5 mm) carrying the full 10 m³/min to junction J1.
- Branch B: 40 m of nominal 40 mm pipe (about 40.9 mm) feeding a production line using 6 m³/min.
- Branch C: 25 m of nominal 25 mm pipe (about 27.2 mm) feeding a packing area using 4 m³/min, needing at least 6.5 bar(g).
| Segment | Flow, m³/min FAD | Velocity, m/s | Pressure drop, bar |
|---|---|---|---|
| Trunk to J1 | 10 | about 10 | about 0.11 |
| Branch B | 6 | about 10 | about 0.10 |
| Branch C (25 mm) | 4 | about 15 | about 0.23 |
| Branch C upsized to 40 mm | 4 | about 7 | about 0.03 |
With the original pipe, the packing area sees about 7.0 − 0.11 − 0.23 = 6.66 bar(g). That looks acceptable on paper, but the margin over 6.5 bar(g) is small, and filters, hoses, quick couplings and regulators at the machine will easily take the rest. Upsizing only branch C, about 25 m of pipe, lifts the node to about 6.86 bar(g). Increasing compressor pressure instead would cost energy across the whole plant to fix one short branch.
Common findings in Indian plants
- Undersized drops and hoses: the header is adequate but the last few metres to the machine, including hose, couplings and filter-regulator, take more pressure than the whole header.
- Extensions added over years: new lines tapped off the far end of an old branch, so a small pipe now carries flow it was never sized for.
- Dead-end headers: long single-ended headers where the far user suffers; closing a ring often helps more than upsizing.
- Corrosion and scale: wet air from a poorly performing dryer rusts steel pipe internally, raising roughness and shedding scale into filters.
- Partly closed or failed valves: found when measured node pressures do not match the model.
- Blocked filters and dryers: treatment losses upstream of the network that look like a distribution problem.
A short pressure survey with calibrated gauges or loggers at the source, at major junctions and at the critical users is the best way to calibrate the model. Our pressure-drop audit page explains how those readings are taken.
How to use the results
- Fix the segment with the largest drop on the critical path first; it usually gives the biggest gain per metre of new pipe.
- Compare a ring closure against upsizing. A ring roughly halves the flow in each path to a remote area and can cut friction loss sharply.
- Check velocities. As a rule of thumb, headers are commonly kept to low velocities, roughly 6–10 m/s, with somewhat higher figures accepted in short drops. Higher velocities raise friction and carry water past drains.
- Once the distribution loss is reduced, review whether the compressor set pressure can come down. That is where the energy saving is realised.
- Build a full source-to-tool pressure budget so treatment, distribution and point-of-use losses are seen together.
Limits of the calculation
The model treats demand as steady. Pulsating users, such as large cylinders or blow-off valves that open together, create short dips that steady-state friction does not show; receiver storage near the user is the usual remedy. Fitting allowances are approximate, and drawings rarely match what is installed. Use the tool to rank options and target measurements, then confirm with field readings before committing to major pipework.
How Reddy Compressors helps
Since 2002 Reddy Compressors has supported plants with multi-brand compressors and complete compressed-air systems. We work independently across ELGi, Atlas Copco, Ingersoll Rand, KAESER, Chicago Pneumatic and other brands, and we are not an authorised distributor of any of them. We have tie-ups with all major and reputed brands.
- Pressure profiling and pressure-drop surveys at the source, junctions and critical users.
- Air audits following the ISO 11011 method (no conformity certificates), including distribution loss and leak findings.
- Practical recommendations on ring mains, branch upsizing, drops and point-of-use storage.
- Service of dryers and filters whose pressure loss shows up as a distribution complaint.
- Rental compressors where a temporary supply is needed while pipework is modified.
Our office is at Tarnaka, Secunderabad. Our service teams cover all of Telangana and Andhra Pradesh, and we supply compressors, rentals and spares across India.
What to send us
- A sketch or drawing of the network with pipe sizes, materials and approximate lengths.
- The compressor and dryer outlet pressure, and the set pressure on each compressor.
- Locations where pressure is low, with the minimum pressure each machine needs.
- Approximate air use of each area or main machine.
- Any pressure readings already taken, with the time of day and production status.
Frequently asked questions
How much pressure drop is acceptable in a compressed air system?
A common design aim is to keep the drop from the compressor outlet to the furthest point of use small, often around 10% of working pressure or less, including treatment, piping and connections. The right figure depends on your machines’ minimum pressure. What matters most is that critical users get their required pressure without raising compressor set pressure, since each extra bar typically costs about 7% more power.
Why is pressure low at the end of my compressed air line?
Low pressure at a remote point is usually caused by an undersized branch or drop, a long dead-end header, a blocked filter or dryer, or extensions added without resizing. Sometimes the compressor simply lacks capacity during peaks. Measuring pressure at the source, at key junctions and at the user, at the same time, quickly shows whether the loss is in treatment, distribution or supply.
Is a ring main better than a straight header?
For plants with users spread around a building, a ring main is usually better. Air can reach each user from two directions, so the flow in each path is lower and friction loss falls sharply. A ring also allows sections to be isolated for maintenance. A straight header can work well for a compact layout, but long dead ends tend to starve the furthest users.
Should I use nominal or internal pipe diameter for pressure drop?
Always use the actual internal diameter. Pressure drop varies roughly inversely with the fifth power of diameter, so a few millimetres matter. Nominal size is only a label; the bore depends on pipe material, wall thickness and grade. Old steel pipe may also have a rougher, partly scaled bore, which increases friction beyond what new-pipe figures suggest.
Can I fix low pressure by increasing the compressor setting?
It may hide the problem, but it is the costliest fix. Higher discharge pressure raises compressor power across all running hours, increases leakage flow through every leak in the plant and pushes unregulated users to consume more air. Fixing the specific restriction on the critical path normally costs less over a year and allows the set pressure to stay where it is or even come down.
Related pages
Calculators and worked examples
These tools give indicative figures for screening, comparison and for preparing an enquiry. They run in your browser and send nothing. No prices or tariffs are assumed: enter your own to see costs. Efficiencies and other figures shown are example values: replace them with your own. Results are not a performance guarantee or a design certificate; final selection is confirmed by a service engineer against the machine data sheet and the site.
Branched network pressure drop
Solve a tree network: a trunk from the source to one junction and up to three branches, each feeding a demand. Find the pressure at each user and the critical branch.
The worked example below shows the method with fixed numbers. Turn on JavaScript to change the inputs.
Worked example
Inputs
- Source pressure (bar g): 7
- Air temperature (°C): 30
- Pipe roughness (mm): 0.046
- Fittings allowance (% extra length): 0
- Trunk: length (m): 60
- Trunk: internal diameter (mm): 52.5
- Branch B: flow (m³/min free air): 6
- Branch B: length (m): 40
- Branch B: internal diameter (mm; needed if it has flow): 40.9
- Branch B: minimum pressure needed (bar g; 0 if not set): 0
- Branch C: flow (m³/min free air): 4
- Branch C: length (m): 25
- Branch C: internal diameter (mm; needed if it has flow): 27.2
- Branch C: minimum pressure needed (bar g; 0 if not set): 6.5
- Branch D: flow (m³/min free air; 0 if unused): 0
- Branch D: length (m): 30
- Branch D: internal diameter (mm; needed if it has flow): 27.2
- Branch D: minimum pressure needed (bar g; 0 if not set): 0
Result
- Trunk: 0.109 bar drop; 10 m³/min at 10.1 m/s
- Junction pressure: 6.89 bar g
- Branch B: 0.099 bar drop; 6 m³/min at 10.2 m/s
- Pressure at user B: 6.79 bar g
- Branch C: 0.231 bar drop; 4 m³/min at 15.4 m/s
- Pressure at user C: 6.66 bar g, margin 0.16 bar over 6.5
- Critical node: User C smallest margin, 0.16 bar
- Largest drop on the critical path: Branch C 0.231 bar of 0.34 bar total
Method. Trunk flow = sum of branch flows. Each segment: Darcy–Weisbach ΔP = f × (L/D) × ρv²/2, Swamee–Jain friction factor, air density at the segment’s mean pressure, flow converted from free air to actual flow at line pressure and temperature. Junction pressure = source − trunk drop; user pressure = junction − branch drop. The critical node is the one with the smallest margin over its minimum pressure. Use real internal diameters; lengths may already include fittings (then enter 0% allowance). This tool solves a single-source tree only (one trunk, one junction, up to three branches). Ring mains, loops (Hardy Cross), several sources and field calibration are NOT solved here; for those, a model is built during a pressure-drop audit. An unused branch (flow 0) is ignored.
What to take from it. Fix the largest drop on the critical path first. Upsizing one short branch is usually far cheaper than raising compressor pressure for the whole plant.
Technical content reviewed by D. Srinivas Reddy, Managing Partner and service engineer, Reddy Compressors. Last updated 7 November 2026. How our engineering content is reviewed.
Pipe pressure drop and sizing
Check the pressure drop and air velocity in a compressed-air line, or find the smallest bore that keeps the drop within a target.
The worked example below shows the method with fixed numbers. Turn on JavaScript to change the inputs.
Worked example
Inputs
- Flow (m³/min free air): 12
- Inlet pressure (bar g): 7
- Pipe length (m): 150
- Inside diameter (mm): 80
- Roughness (mm): 0.046
- Fittings allowance (% extra length): 30
- Air temperature (°C): 30
- Target pressure drop (bar): 0.1
Result
- Pressure drop: 0.059 bar (0.839% of the inlet gauge pressure)
- Air velocity: 5.22 m/s
- Reynolds number: 2,06,066
- Smallest bore for the target drop: 73 mm inside diameter
- Velocity check: Within the common rule-of-thumb range for mains (roughly up to 15–20 m/s)
Method. Darcy–Weisbach: ΔP = f × (L/D) × ρv²/2, with the friction factor f from the Swamee–Jain relation and air density taken at mean line pressure. Fittings are allowed for as extra equivalent length. Typical commercial steel roughness is about 0.046 mm.
What to take from it. Pressure drop varies roughly with the fifth power of the bore at constant flow, so a larger main is a cheap way to hold pressure.