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REDDY COMPRESSORS

Pneumatic applications

Pneumatic cylinder sizing and motion control

9 min read12 sections

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Start with a cylinder-duty brief

Before opening a catalogue, write down what the cylinder must actually do. Most poor selections start with a bore chosen “the same as the last machine” and are then patched with higher pressure. A short duty brief avoids that:

  • Task: push, pull, lift, clamp, press, index or hold.
  • Force required at the load in each direction, including friction and any process force.
  • Moving mass, including tooling and the piston and rod.
  • Orientation: horizontal, vertical up, vertical down or inclined.
  • Stroke and the position of any intermediate stops.
  • Required travel time or cycle rate.
  • Minimum supply pressure at the machine, not the compressor-room setting.
  • Behaviour on loss of air or electrical power: hold, return, exhaust or lock.
  • Environment: dust, washdown, heat, food contact or welding spatter.

How to calculate cylinder force correctly

Force is pressure multiplied by effective area. On a double-acting cylinder the two directions are different:

  • Extension (push) area is the full piston area: A = π × D² / 4.
  • Retraction (pull) area is the annulus: A = π × (D² − d²) / 4, where d is the rod diameter.

At 1 bar, each square centimetre of area gives about 10 N. So a 63 mm bore (about 31.2 cm²) at 6 bar gauge gives a theoretical push of roughly 1,870 N. With a 20 mm rod, the annulus is about 28.0 cm² and the theoretical pull at 6 bar is roughly 1,680 N.

That theoretical figure is a ceiling, not a working value. Seal friction typically takes a small part of it, and the opposing chamber often holds back-pressure while it exhausts. The useful force balance is:

Net force = (pressure in driving chamber × driving area) − (pressure in exhausting chamber × exhausting area) − friction − load.

If exhaust flow is restricted by a meter-out flow control, a small silencer or a long exhaust line, the exhausting chamber can hold significant pressure during the stroke. A cylinder that looks generous on a static calculation can then stall or slow.

Set a pressure envelope, then choose the bore

Size against the minimum pressure the cylinder will actually see during operation, not the nominal header pressure. In most Indian plants the header is somewhere around 6–7 bar (87–101.5 psig), but machines at the end of long lines, or during peak demand, may see much less. Record:

  • Minimum dynamic pressure at the valve inlet during the busiest part of the shift.
  • Regulator setting at the machine.
  • Maximum pressure the cylinder, tooling and product can safely tolerate.

Then select the smallest standard bore that delivers the required force at minimum pressure with a stated margin. For dynamic duties a load ratio (load ÷ theoretical force) of about 0.5 is a common starting point, rising towards about 0.7 for slow, near-static duties. State the margin in the duty record so the next engineer can see it.

Bore (mm)Piston area (cm²)Theoretical push at 6 bar (N)Typical rod (mm)Theoretical pull at 6 bar (N)
328.0≈ 48012≈ 415
4012.6≈ 75016≈ 630
5019.6≈ 1,18020≈ 990
6331.2≈ 1,87020≈ 1,680
8050.3≈ 3,02025≈ 2,720
10078.5≈ 4,71025≈ 4,420

These are calculated values before friction and back-pressure; rod sizes vary between makers, so use the actual data sheet.

Stroke, mounting, guidance and rod stability

Long strokes and pushing duties raise the risk of rod buckling, particularly with a pivot mounting at both ends. Check the maker’s buckling chart for the chosen mounting and stroke. Where the load runs off-centre or has side forces, add external guides or use a guided cylinder; the rod bearing is not designed to carry heavy side loads, and it will wear quickly if it does.

Also confirm the end positions. If the cylinder is used as the mechanical stop, its end cover and cushioning take the full stopping energy every cycle. Where accuracy matters, use an external stop and let the cylinder push against it.

Speed, valve flow and stopping the load

Travel time depends on how quickly the valve and tubing can fill the driving chamber and empty the other. Average air consumption does not show this. A valve that is ample on a cycle-average basis can still be too small to move the cylinder in the required time.

  1. Calculate the required mean piston speed: stroke ÷ travel time.
  2. Estimate the flow needed during the stroke: piston area × speed, converted to free air at the working pressure.
  3. Check the valve’s flow rating (Cv, Kv or the maker’s standard nominal flow) against that figure, including fittings and tube bore.
  4. Choose speed control: meter-out flow control is the usual choice for double-acting cylinders, because it holds the load against the exhaust air and gives steadier motion.
  5. Check stopping: kinetic energy at the end of stroke (½ × mass × speed²) must be within the cushion’s capacity. A descending vertical load also adds gravitational energy, so it needs more stopping capacity than the same mass moving horizontally.
  6. Add shock absorbers or external stops where cushioning is insufficient.

Very slow speeds bring stick-slip, where the piston jerks forward as static friction breaks. Low-friction seals, careful meter-out setting, adequate supply pressure and, where needed, a hydraulic check unit help. For intermediate stopping and holding, standard pneumatic cylinders are not precise; use rod locks, mechanical stops or a different actuator.

Choose the right actuator architecture

TypeSuitsWatch for
Single-acting, spring returnShort strokes, clamping, fail-safe returnSpring reduces force; return speed fixed by spring
Double-actingMost industrial motion in both directionsNeeds a 5/2 or 5/3 valve; both directions sized separately
Guided cylinderSide loads, anti-rotation, toolingGuide load ratings and deflection
Rodless cylinderLong strokes in short spaceSeal band wear, moment loads
Rotary actuatorIndexing, valve operationTorque at minimum pressure, stopping inertia
Cylinder with rod lockHolding position on air lossLock is for holding, not for dynamic braking unless rated

Valve choice also sets the behaviour on loss of air or power. A 5/3 closed-centre valve traps air, an exhaust-centre valve vents both chambers and a pressure-centre valve pressurises both. Which is correct depends on the machine’s risk assessment, not on habit.

Air quality and air consumption

Cylinders need dry, filtered air at a stable pressure. Water and pipe scale strip lubrication from seals and cause sticking, especially in humid monsoon months. Most modern cylinders are pre-lubricated for life; once oil is added through a lubricator, it usually has to continue. Fit an FRL suited to the duty; our page on end-use air preparation and FRL selection covers this.

Air consumption per cycle is the swept volume of both strokes plus dead volume in tubes and ports, multiplied by the pressure ratio ((gauge pressure + 1.013) ÷ 1.013). For example, a 63 mm bore with a 20 mm rod and a 200 mm stroke at 6 bar uses about 0.62 litre on extension and 0.56 litre on retraction as swept volume, or about 8.2 free litres per complete cycle once multiplied by a pressure ratio of about 6.9. At 10 cycles per minute that is about 82 litres per minute (about 2.9 cfm), plus tubing dead volume. Long tubes between valve and cylinder can add noticeably to that figure, so mount valves close to the cylinder where practical. Our cylinder consumption calculator works through this.

Diagnose motion problems before enlarging the cylinder

When a cylinder is slow, weak or erratic, a larger bore is rarely the first fix. Check in this order:

  1. Measure pressure at the valve inlet and, if possible, in both cylinder ports during the stroke.
  2. Look for restricted exhaust: blocked silencers, over-closed flow controls, undersized fittings.
  3. Check supply line pressure drop and FRL condition during peak demand.
  4. Check seals for bypass by pressurising one side and listening or measuring at the other port.
  5. Check for side loads, misalignment or binding guides.
  6. Only then reconsider bore, valve size or actuator type.

Low header pressure caused by leaks or an overloaded compressor shows up first on cylinders at the end of the line. Fixing the supply is often cheaper than resizing several machines.

How Reddy Compressors helps

We work on the compressed-air supply that cylinders and pneumatic machines depend on. From our office at Tarnaka, Secunderabad, and with over 20 service engineers and technicians, we serve plants across Telangana and Andhra Pradesh and supply equipment and spares across India.

  • Pressure and flow logging at machines to show what pressure cylinders actually receive during peak demand.
  • Air audits, leak surveys and pressure-drop checks on distribution lines.
  • Sales of new and used/refurbished compressors, dryers, filters and receivers, multi-brand and independent (not an authorised dealer). We have tie-ups with all major and reputed brands.
  • Service, AMC and spare parts for compressors and air treatment.
  • Rental compressors from our own fleet for trials, shutdowns or breakdown cover.

We do not supply machine-safety approvals or design the machine circuit; where that is needed, the duty record above is what your machine builder needs.

What to send us

  • Machine or line description and the number of cylinders.
  • Bore, rod, stroke and cycle rate of the main cylinders.
  • Pressure readings at the machine during normal and peak operation.
  • Compressor make, model, nameplate photo and set pressure.
  • Dryer and filter details, and any water or oil seen at the machines.
  • The symptom: slow, weak, erratic, or high air use.

Frequently asked questions

How do I calculate the force of a pneumatic cylinder?

Multiply the gauge pressure by the effective area. For push, use the full piston area, π × D² ÷ 4; for pull, subtract the rod area. At 1 bar each square centimetre gives about 10 N, so a 50 mm bore at 6 bar gives about 1,180 N theoretical push. Then deduct friction and any exhaust back-pressure, and apply a load ratio margin before choosing the bore.

Why is my pneumatic cylinder moving slowly?

The usual causes are low pressure at the valve during peak demand, a valve or tubing too small for the required flow, restricted exhaust from blocked silencers or over-closed flow controls, worn seals letting air bypass, or binding from side loads. Measure pressure at the cylinder ports during the stroke before changing anything. Raising compressor pressure costs about 7% more power per bar and may not fix it.

What pressure should a pneumatic cylinder be sized for?

Size for the minimum dynamic pressure the cylinder will see at its valve during the busiest part of the shift, not the compressor setting. Many plants run their headers at about 6–7 bar (87–101.5 psig), but machines at the end of long lines may receive much less. Choosing the bore at the lower figure keeps the machine working when demand peaks.

How much air does a pneumatic cylinder use?

Calculate the swept volume of both strokes plus tube and port dead volume, then multiply by the pressure ratio, which at 6 bar gauge is about 6.9. A 63 mm cylinder with a 200 mm stroke uses roughly 8 free litres per cycle at 6 bar. Multiply by cycles per minute and by the number of cylinders to estimate demand, then add allowances for leaks.

Should I use meter-in or meter-out flow control on a cylinder?

For most double-acting cylinders, meter-out control is preferred because it controls the air leaving the cylinder, which holds the load against a cushion of air and gives steadier speed, especially with varying or overrunning loads. Meter-in is mainly used on single-acting cylinders or special cases. Over-closing meter-out control raises back-pressure, so set it while watching force and travel time.

What causes jerky movement in a pneumatic cylinder at low speed?

Jerky motion, or stick-slip, happens when seal friction holds the piston until pressure builds, then releases suddenly. It is worse at very low speeds, with dry or worn seals, wet air and low supply pressure. Low-friction seals, clean dry air, correct meter-out settings and sometimes a hydraulic check unit reduce it. Very slow, smooth motion may need a different actuator altogether.

Calculators and worked examples

These tools give indicative figures for screening, comparison and for preparing an enquiry. They run in your browser and send nothing. No prices or tariffs are assumed: enter your own to see costs. Efficiencies and other figures shown are example values: replace them with your own. Results are not a performance guarantee or a design certificate; final selection is confirmed by a service engineer against the machine data sheet and the site.

Pneumatic cylinder force and bore selection

Theoretical push and pull force from bore, rod and the minimum dynamic pressure, the force left after exhaust back-pressure and your load ratio, the smallest standard bore for a required force, and the speed, flow and end-of-stroke energy for a travel time.

The worked example below shows the method with fixed numbers. Turn on JavaScript to change the inputs.

Worked example

Inputs
  • Bore (mm): 63
  • Rod diameter (mm): 20
  • Minimum dynamic pressure at the valve (bar g): 6
  • Back-pressure in the exhausting chamber (bar g): 0
  • Working direction: Push (extend)
  • Force required at the load (N; 0 to skip bore selection): 800
  • Load ratio (load ÷ theoretical force): 0.5
  • Stroke (mm): 200
  • Travel time (s; 0 to skip): 0.5
  • Moving mass (kg; 0 to skip): 10
Result
  • Piston area / annulus area: 31.17 / 28.03 cm²
  • Theoretical push / pull force: 1,870 / 1,682 N at 6 bar g (87 psi)
  • Net force, push: 1,870 N before friction
  • Usable force at load ratio 0.5: 935 N
  • Theoretical force needed: 1,600 N (800 N ÷ 0.5)
  • Pressure this bore needs for it: 5.13 bar g (74.4 psi): within the minimum available
  • Smallest standard bore for that force: 63 mm (rod 20 mm) gives 1,870 N push at 6 bar g
  • Mean piston speed: 0.4 m/s
  • Free-air flow during the stroke: 8.63 L/s = 0.518 m³/min = 518 L/min = 18.3 cfm (valve, tubing and fittings must pass this)
  • Kinetic energy at mean speed: 0.8 J: compare with the cushion or shock-absorber rating

Method. Push area A = π × D² ÷ 4; pull (annulus) area = π × (D² − d²) ÷ 4. Force (N) = pressure (bar g) × area (cm²) × 10, since 1 bar on 1 cm² ≈ 10 N. Net force = driving pressure × driving area − exhaust back-pressure × exhausting area (friction and load still to come off). Theoretical force needed = load ÷ load ratio (about 0.5 for dynamic duties, up to about 0.7 for slow, near-static duties). The smallest standard bore is the first in the series 12–320 mm (typical rods as in the table on the page; check the data sheet) whose net force in that direction reaches the force needed. Mean speed = stroke ÷ travel time; free-air flow during the stroke = area × speed × (p + 1.013) ÷ 1.013; kinetic energy = ½ m v² at mean speed (the real end speed can be higher; a descending vertical load adds gravitational energy).

What to take from it. Size against the lowest pressure the cylinder sees in operation, with a stated load ratio. A cylinder that looks generous on paper can stall when its exhaust side holds back-pressure.

Technical content reviewed by D. Srinivas Reddy, Managing Partner and service engineer, Reddy Compressors. Last updated 17 October 2026. How our engineering content is reviewed.

Pneumatic cylinder air consumption

Work out the free air a cylinder uses per cycle and per minute.

The worked example below shows the method with fixed numbers. Turn on JavaScript to change the inputs.

Worked example

Inputs
  • Bore (mm): 63
  • Stroke (mm): 200
  • Working pressure (bar g): 6
  • Cycles per minute: 20
  • Number of cylinders: 8
  • Double acting? (2 = yes, 1 = single): 2
  • Rod diameter (mm; 0 to ignore): 20
Result
  • Free air per cycle (each): 8.2 litres
  • Total consumption: 21.9 L/s
  • 1.311 m³/min = 46.3 cfm
  • Theoretical force, outstroke: 1,870 N (before friction; allow 10–20% less)
  • Theoretical force, return stroke: 1,682 N

Method. Air per stroke (free air) = swept area × stroke × (P + 1.013) / 1.013. The outstroke uses the full bore area π/4 × D²; the return stroke of a double-acting cylinder uses the bore area less the rod area π/4 × d². Enter rod 0 to ignore it (a small over-estimate).

What to take from it. Many small cylinders add up. Reducing stroke, pressure or cycle rate lowers consumption in direct proportion.

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